In the reaction CH_3-CH=CH_2 + H_2O + [O] xri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction involves the oxidation of propene to propane-$1,2$-diol,followed by oxidative cleavage.The cleavage of propane-$1,2$-diol $(CH_3-CH(O

Vedclass · Accepted Answer

$CH_3-COOH$

Vedclass · Answer

(B) The reaction involves the oxidation of propene to propane-$1,2$-diol,followed by oxidative cleavage.The cleavage of propane-$1,2$-diol $(CH_3-CH(OH)-CH_2(OH))$ using an oxidizing agent leads to the breaking of the $C-C$ bond between the two hydroxyl-bearing carbons.This process yields ethanoic acid $(CH_3COOH)$ and methanoic acid $(HCOOH)$.Therefore,$X$ is $CH_3COOH$.

In the reaction $CH_3-CH=CH_2 + H_2O + [O]$ $\xrightarrow[Acid]{KMnO_4} CH_3-CH(OH)-CH_2(OH)$ $\xrightarrow{[O]} X + HCOOH$,$X$ is:

Similar Questions

Baeyer's reagent is used in the laboratory for

Which of the following reagents can be used to convert propene into propan-$1$-ol?

What is obtained when propene is treated with $N$-bromosuccinimide?

$HO - CH_2 - CH_2 - CH_2 - CH_2 - CH = CH_2 \xrightarrow{Br_2} \text{Product ?}$

What do you mean by alkene? Give its general formula and two examples.

Vedclass Test Series

Exam Paper Generator

Online Exam Module